document.write( "Question 439867: In a spanish deck of cards; how many ways can you make a full house? \n" ); document.write( "
Algebra.Com's Answer #304007 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "A traditional Spanish deck is not an ordinary deck. It\r\n" );
document.write( "has 40 cards, not 52.  It consists of four suits of ten \r\n" );
document.write( "numbered cards (1-7, and 10-12, with 10,11 and 12 being\r\n" );
document.write( "picture cards). [There are no 8s or 9s]\r\n" );
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document.write( "A full house consists of 5 cards, a pair and a 3-of-a-kind.\r\n" );
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document.write( "We can choose the number for the pair as any of 10 numbers.\r\n" );
document.write( "For each of those 10 ways to choose the number for the pair,\r\n" );
document.write( "we can choose the suits for the pair any of 4C2 ways. That's \r\n" );
document.write( "10*4C2 ways.  \r\n" );
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document.write( "For each of these 10*4C2 ways to choose a number and suits\r\n" );
document.write( "for the pair, we can choose the number for the 3-of-a-kind \r\n" );
document.write( "as any of the 9 numbered cards that we did not choose for\r\n" );
document.write( "the pair.  For each of those 9 ways to choose the number \r\n" );
document.write( "for the 3-of-a-kind, we can choose the suits for the \r\n" );
document.write( "3-of-a-kind any of 4C3 ways.  That's 9*4C3 to pick the\r\n" );
document.write( "3-of-a-kind for each of the 10*4C2 ways to pick the pair.\r\n" );
document.write( "So the answer is\r\n" );
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document.write( "10*4C2*9*4C3 = 2160 ways.\r\n" );
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document.write( "Edwin
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