document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=439890>Question 439890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me on this problem?<BR>\n" );
document.write( "Tennis balls are packaged three to a cylindrical can. If the diameter of a tennis ball is 2 1/2 inches, find the volume of the can.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303988 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tennis balls are packaged three to a cylindrical can. If the diameter of a tennis ball is 2 1/2 inches, find the volume of the can. <BR>\n" );
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document.write( "The height of the can is 3*diameter of a ball = 3*(5/2) = 15/2 inches<BR>\n" );
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document.write( "Diameter of the base = diameter of a ball = 5/2 inches.<BR>\n" );
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document.write( "Volume = Area of base*height<BR>\n" );
document.write( "Vol = (pi)*(5/4)^2*(5/2)<BR>\n" );
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document.write( "Vol = 3.906(pi) cu. in.<BR>\n" );
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document.write( "Vol = 12.2718 cu. in.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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