document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=439776>Question 439776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the digits of a two digit number is 7. if the digits are reversed, the newly formed number is 9 larger than the original number. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303946 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=7<BR>\n" );
document.write( "10x+y=10y+x-9<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "y=7-x<BR>\n" );
document.write( "10x+(7-x)=10(7-x)+x-9<BR>\n" );
document.write( "9x+7=70-10x+x-9<BR>\n" );
document.write( "\"\"=61-9x<BR>\n" );
document.write( "18x=54<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "y=4<BR>\n" );
document.write( "The original number is 34. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );