document.write( "Question 439747: A rectangle has 200 feet of fencing with which to enclose two adjacent rectangle corrals. What dimensions should be used so the enclosed area will be a maximum? what is the maximum area? \n" ); document.write( "
Algebra.Com's Answer #303916 by stanbon(75887)\"\" \"About 
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A rectangle has 200 feet of fencing with which to enclose two adjacent rectangle corrals. What dimensions should be used so the enclosed area will be a maximum? what is the maximum area?
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\n" ); document.write( "Draw the picture of 2 adjacent rectangles.
\n" ); document.write( "Let height be \"h\" (Note: there are 3 of them)
\n" ); document.write( "Then width = (1/2)(200-3h)
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\n" ); document.write( "Area = (h/2)(200-3h)
\n" ); document.write( "Area = 100h - (3/2)h^2
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\n" ); document.write( "Max area occurs when
\n" ); document.write( "h = -b/(2a)
\n" ); document.write( "= -100/(2(-3/2))
\n" ); document.write( "= 100/3 ft.
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\n" ); document.write( "Then length = (1/2)(200-(3/2)(100/3))
\n" ); document.write( "= (1/2)(50)
\n" ); document.write( "= 25 ft.
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\n" ); document.write( "Max area = 25*(100/3) = 833 1/3 sq. ft.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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