document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=439685>Question 439685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the perimeter of a rectangle is 112 meter, and the length is one meter shorter than twice the width, then what is the length and the width<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303852 by </B><A HREF=/tutors/aboutme.mpl?userid=asuar010><B>asuar010(338)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=asuar010><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=asuar010><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303852\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the perimeter formula for a rectangle is P=2(l+w) l=lenght, w=width\r<BR>\n" );
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document.write( "by interpreting the problem we assign x as the width and 2x-1 as the length...<BR>\n" );
document.write( "w=x<BR>\n" );
document.write( "l=2x-1\r<BR>\n" );
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document.write( "by substituting the values we get:<BR>\n" );
document.write( "112=2(x+2x-1) then 112=2(3x-1) then 112=6x-2 then 114=6x and we obtain x=19.\r<BR>\n" );
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document.write( "then by subtituting the value of x we get that w=19 and l=2(19)-1=37 </SPAN>\n" );
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