document.write( "Question 439571: How many liters of a 10% alcohol solution must be mixed wih 40L of a 50% solution to get a 40% solution \n" ); document.write( "
Algebra.Com's Answer #303845 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
40L of a 50% solution equals 20L of pure alcohol.
\n" ); document.write( ".10x+.50(40)=.40(x+40)
\n" ); document.write( ".10x+20=.4x+16
\n" ); document.write( "4=.3x
\n" ); document.write( "4/.3=x
\n" ); document.write( "13.33=x
\n" ); document.write( "You need 13 1/3 liters of a 10% solution to mix up a 40% solution..
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