document.write( "Question 439571: How many liters of a 10% alcohol solution must be mixed wih 40L of a 50% solution to get a 40% solution \n" ); document.write( "
Algebra.Com's Answer #303845 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 40L of a 50% solution equals 20L of pure alcohol. \n" ); document.write( ".10x+.50(40)=.40(x+40) \n" ); document.write( ".10x+20=.4x+16 \n" ); document.write( "4=.3x \n" ); document.write( "4/.3=x \n" ); document.write( "13.33=x \n" ); document.write( "You need 13 1/3 liters of a 10% solution to mix up a 40% solution.. \n" ); document.write( " |