document.write( "Question 439661: Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by S(t) = 68 -20 log (t + 1), t ≥ 0. \r
\n" ); document.write( "\n" ); document.write( "After what time t was the average score 50%?\r
\n" ); document.write( "\n" ); document.write( "This is all I got so far... I do not know where to start or finish please help! thank you.\r
\n" ); document.write( "\n" ); document.write( " .5= 68 - 20 log (t + 1), t ≥ 0. \n" ); document.write( "
Algebra.Com's Answer #303817 by stanbon(75887)\"\" \"About 
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Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by S(t) = 68 -20 log (t + 1), t ≥ 0.
\n" ); document.write( "After what time t was the average score 50%?
\n" ); document.write( "This is all I got so far... I do not know where to start or finish please help! thank you.
\n" ); document.write( "50 = 68 - 20 log (t + 1), t ≥ 0.
\n" ); document.write( "----
\n" ); document.write( "-18 = -20*log(t+1)
\n" ); document.write( "---
\n" ); document.write( "0.9 = log(t+1)
\n" ); document.write( "----
\n" ); document.write( "t+1 = 10^0.9
\n" ); document.write( "---
\n" ); document.write( "t = 7.943.. -1
\n" ); document.write( "---
\n" ); document.write( "t = 6.943 months
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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