document.write( "Question 439599: $9500 is invested, part of it at 10% and part of it at 6%. for a certain year, the total yield is $806.00. how much was invested? \n" ); document.write( "
Algebra.Com's Answer #303814 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! x+y=9500 \n" ); document.write( ".1x+.06y=806 \n" ); document.write( "Multiply the second equation by 100: \n" ); document.write( "10x+6y=80600 \n" ); document.write( "6x+6y=57000 \n" ); document.write( "4x=23600 \n" ); document.write( "x=5900 \n" ); document.write( "y=3600 \n" ); document.write( "$5900 was invested at 10%, $3600 was invested at 6%.. \n" ); document.write( " |