document.write( "Question 439599: $9500 is invested, part of it at 10% and part of it at 6%. for a certain year, the total yield is $806.00. how much was invested? \n" ); document.write( "
Algebra.Com's Answer #303814 by jorel1380(3719)\"\" \"About 
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x+y=9500
\n" ); document.write( ".1x+.06y=806
\n" ); document.write( "Multiply the second equation by 100:
\n" ); document.write( "10x+6y=80600
\n" ); document.write( "6x+6y=57000
\n" ); document.write( "4x=23600
\n" ); document.write( "x=5900
\n" ); document.write( "y=3600
\n" ); document.write( "$5900 was invested at 10%, $3600 was invested at 6%..
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