document.write( "Question 439578: simplify \r
\n" ); document.write( "\n" ); document.write( "y^2-16 / y^2-8y+6
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Algebra.Com's Answer #303771 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"y%5E2-16+%2F+y%5E2-8y%2B6\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2-4%5E2+%2F+y%5E2-8y%2B6\"..........\"y%5E2-8y%2B6\" complete the square \r
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Solved by pluggable solver: COMPLETING THE SQUARE solver for quadratics
Read this lesson on completing the square by prince_abubu, if you do not know how to complete the square.
Let's convert \"1x%5E2%2B-8x%2B6=0\" to standard form by dividing both sides by 1:
\n" ); document.write( "We have: \"1x%5E2%2B-8x%2B6=0\". \n" ); document.write( "What we want to do now is to change this equation to a complete square \"%28x%2Bsomenumber%29%5E2+%2B+othernumber\". How can we find out values of somenumber and othernumber that would make it work?
\n" ); document.write( "Look at \"%28x%2Bsomenumber%29%5E2\": \"%28x%2Bsomenumber%29%5E2+=+x%5E2%2B2%2Asomenumber%2Ax+%2B+somenumber%5E2\". Since the coefficient in our equation \"1x%5E2%2Bhighlight_red%28+-8%29+%2A+x%2B6=0\" that goes in front of x is -8, we know that -8=2*somenumber, or \"somenumber+=+-8%2F2\". So, we know that our equation can be rewritten as \"%28x%2B-8%2F2%29%5E2+%2B+othernumber\", and we do not yet know the other number.
\n" ); document.write( "We are almost there. Finding the other number is simply a matter of not making too many mistakes. We need to find 'other number' such that \"%28x%2B-8%2F2%29%5E2+%2B+othernumber\" is equivalent to our original equation \"1x%5E2%2B-8x%2Bhighlight_green%28+6+%29=0\".
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\n" ); document.write( " The highlighted red part must be equal to 6 (highlighted green part).
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\n" ); document.write( " \"-8%5E2%2F4+%2B+othernumber+=+6\", or \"othernumber+=+6--8%5E2%2F4+=+-10\".
\n" ); document.write( "So, the equation converts to \"%28x%2B-8%2F2%29%5E2+%2B+-10+=+0\", or \"%28x%2B-8%2F2%29%5E2+=+10\".
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\n" ); document.write( " Our equation converted to a square \"%28x%2B-8%2F2%29%5E2\", equated to a number (10).
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\n" ); document.write( " Since the right part 10 is greater than zero, there are two solutions:
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\n" ); document.write( " \"system%28+%28x%2B-8%2F2%29+=+%2Bsqrt%28+10+%29%2C+%28x%2B-8%2F2%29+=+-sqrt%28+10+%29+%29\"
\n" ); document.write( " , or
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\n" ); document.write( " \"system%28+%28x%2B-8%2F2%29+=+3.16227766016838%2C+%28x%2B-8%2F2%29+=+-3.16227766016838+%29\"
\n" ); document.write( " \"system%28+x%2B-8%2F2+=+3.16227766016838%2C+x%2B-8%2F2+=+-3.16227766016838+%29\"
\n" ); document.write( " \"system%28+x+=+3.16227766016838--8%2F2%2C+x+=+-3.16227766016838--8%2F2+%29\"
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\n" ); document.write( " \"system%28+x+=+7.16227766016838%2C+x+=+0.83772233983162+%29\"
\n" ); document.write( "Answer: x=7.16227766016838, 0.83772233983162.\n" ); document.write( "

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\n" ); document.write( "\n" ); document.write( "use:\"%28y+-8%2F2%29%5E2-10\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28y-4%29%28y%2B4%29%29+%2F+%28%28y+-8%29%2F2%29%5E2-10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28y-4%29%28y%2B4%29%29+%2F+%28%282y+-8%29%2F2%29%5E2-10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28y-4%29%28y%2B4%29%29+%2F+%28%28%282y+-8%29%282y+-8%29%29-10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28y-4%29%28y%2B4%29%29+%2F+%28%282%28y+-4%29%282y+-8%29%29-10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28cross%28%28y-4%29%29%28y%2B4%29%29+%2F+%28%282cross%28%28y+-4%29%29%282y+-8%29%29-10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B4%29+%2F+%282%282y+-8%29-10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B4%29+%2F+%284y+-16-10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B4%29+%2F+%284y+-26%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B4%29+%2F+2%282y+-13%29\"\r
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