document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=439504>Question 439504</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a triangle sides 2y, 6y, and y + 7. what is the perimeter of the triangle when y=3? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303759 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem is flawed. Normally, the perimeter would be 2y + 6y + (y+7) = 9y + 7 = 27 + 7 = 34, but if you substitute y first, you obtain a \"triangle\" with sides 6, 18, and 10. This is not a triangle, because 6 + 10 < 18, which violates the triangle inequality. </SPAN>\n" );
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