document.write( "Question 439520: hello. i need help with these few problems. \"+log+%28+2%2C+25+%29+\" and \"+log+%28+2%2C+3%2F5+%29+\" and \"+log+%28+2%2C+15+%29+\" and \"+log+%28+2%2C+75+%29+\" i just dont know how to approach these. Thanks \n" ); document.write( "
Algebra.Com's Answer #303740 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
log ( 2, 25 ) }}} and \"+log+%28+2%2C+3%2F5+%29+\" and \"+log+%28+2%2C+15+%29+\" and \"+log+%28+2%2C+75+%29+\"
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\n" ); document.write( "There is a Law of Logs called the change of base law.
\n" ); document.write( "It says: loga(b) = logc(b)/logc(a)
\n" ); document.write( "where c is any base you care to use.
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\n" ); document.write( "Your problem:
\n" ); document.write( "log2(25) = log(25)/log(2) = 1.3979/0.3010 = 4.644
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\n" ); document.write( "Using your calculator:
\n" ); document.write( "log2(3/5) = log(3/5)/log(2) = -0.7370
\n" ); document.write( "---
\n" ); document.write( "log2(75) = log(75)/log(2) = 6.2288
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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