document.write( "Question 439497: Perimeter of rectangle is 28 feet. The difference between 4 times the length and 3 times the width is 21 feet. What is the dimension. Please clear, precise instructions. \n" ); document.write( "
Algebra.Com's Answer #303736 by stanbon(75887)\"\" \"About 
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Perimeter of rectangle is 28 feet. The difference between 4 times the length and 3 times the width is 21 feet. What is the dimension.
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\n" ); document.write( "Perimeter = 2(length + width)
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\n" ); document.write( "4L-3W = 21
\n" ); document.write( "W = (4L-21)/3
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\n" ); document.write( "Equation:
\n" ); document.write( "28 = 2(L + [(4L-21)/3])
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\n" ); document.write( "14 = (L + (4/3)L - 7)
\n" ); document.write( "14 = (7/3)L - 7
\n" ); document.write( "21 = (7/3)L
\n" ); document.write( "L = (3/21)7
\n" ); document.write( "Length = 1 ft.
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\n" ); document.write( "Solve for \"w\":
\n" ); document.write( "W = (4*1-21)/3
\n" ); document.write( "W = -17/3 ft.
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\n" ); document.write( "That doesn't make any sense. Width cannot be negative.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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