document.write( "Question 45738: substitution method\r
\n" ); document.write( "\n" ); document.write( "y=13-3x
\n" ); document.write( "2x+9y=-8
\n" ); document.write( "

Algebra.Com's Answer #30373 by fazlerabbi(9)\"\" \"About 
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Given,
\n" ); document.write( " y = 13 - 3x ----- (1)
\n" ); document.write( " 2x + 9y = -8 ----- (2)\r
\n" ); document.write( "\n" ); document.write( "Substituting value of y in (2) from (1) we get
\n" ); document.write( " 2x+9(13-3x) = -8
\n" ); document.write( "=> 2x+117-27x = -8
\n" ); document.write( "=> 117-25x = -8
\n" ); document.write( "=> 117-25x-117 = -8-117 ;(adding -117 to both sides)
\n" ); document.write( "=> -25x = -125
\n" ); document.write( "=> x = 5 ;(multiplying both sides by 1/-25) \r
\n" ); document.write( "\n" ); document.write( "Substituting the value of x in (1) we get
\n" ); document.write( " y = 13 - 3(5)
\n" ); document.write( " =>y = 13 - 15
\n" ); document.write( " =>y = -2 \r
\n" ); document.write( "\n" ); document.write( "So, Answer is x=5, y=-2
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