document.write( "Question 439483: Good morning!
\n" ); document.write( "Alas... in need of help on a very simple problem.\r
\n" ); document.write( "\n" ); document.write( "tan^2(3x) = 3
\n" ); document.write( "I am unsure of where exactly to start on this problem. Have applied the trig identity for tan^2(x) which is (1-cos2x)/(1+cos2x) but am not sure if that is the correct way to go. Please break down and explain!\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #303728 by Gogonati(855)\"\" \"About 
You can put this solution on YOUR website!
\"%28tan%283x%29%29%5E2=3\" is a trigonometric equation.Taking the square root of both \r
\n" ); document.write( "\n" ); document.write( "sides of the equation, we have two equivalent equations: \r
\n" ); document.write( "\n" ); document.write( "\"tan%283x%29=sqrt%283%29\",(1) and, \"tan%283x%29=-sqrt%283%29\", (2).\r
\n" ); document.write( "\n" ); document.write( "As you know the function tan(x) is periodic function with period \"pi\".\r
\n" ); document.write( "\n" ); document.write( "Solving each of them we have:\"3x=n%2Api%2B%28pi%29%2F3\"=> \"x=n%2Api%2B%28pi%29%2F9\" and\r
\n" ); document.write( "\n" ); document.write( "\"x=n%2Api%2B%284%2Api%29%2F9\", for equation (1).\r
\n" ); document.write( "\n" ); document.write( "\"3x=n%2Api-%28pi%29%2F3\" => \"x=n%2Api-%28pi%29%2F9\" and \"x=n%2Api-%282%2Api%29%2F9\"\r
\n" ); document.write( "\n" ); document.write( "for equation (2)
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