document.write( "Question 439458: Can someone please help me with this problem? Thank you so much.\r
\n" ); document.write( "\n" ); document.write( "The braking distance D in feet required to stop a car traveling x mph on dry, level pavement can be approximated by D= 1/9x^2
\n" ); document.write( "(a.) Calculate the braking distance for 30 mph and 60 mph. how do your answers compare?
\n" ); document.write( "(b.) If the braking distance is 16 feet, estimate the speed of the car.
\n" ); document.write( "(c.) Use a calculator to solve part (b) numerically. Do your answers agree?
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Algebra.Com's Answer #303715 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The braking distance D in feet required to stop a car traveling x mph on dry, level pavement can be approximated by D= (1/9)x^2
\n" ); document.write( "(a.) Calculate the braking distance for 30 mph and 60 mph. how do your answers compare?
\n" ); document.write( "D(30) = (1/9)*30^2 = 100 ft.
\n" ); document.write( "D(60) = (1/9)*60^2 = 400 ft.
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\n" ); document.write( "\n" ); document.write( "(b.) If the braking distance is 16 feet, estimate the speed of the car.
\n" ); document.write( "16 = (1/9)r^2
\n" ); document.write( "r^2 = 16/9
\n" ); document.write( "r = 4/3 mph = 1 1/3 mph
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\n" ); document.write( "(c.) Use a calculator to solve part (b)
\n" ); document.write( "numerically. Do your answers agree?
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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