document.write( "Question 439435: 2.The area of a rectangular tabletop is 6 square feet. If the width is 2 feet shorter than the length, then what are the dimensions? (You will need to use either completing the square or the quadratic formula. Round your answers with a calculator to 2 decimal places) \r
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Algebra.Com's Answer #303699 by Gogonati(855)\"\" \"About 
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let the length = x feet, then the width is: x-2 feet, and the area is:\r
\n" ); document.write( "\n" ); document.write( "\"x%28x-2%29=6\", set this equation to zero: \"x%5E2-2x-6=0\", solving this \r
\n" ); document.write( "\n" ); document.write( "quadratic function by factoring: \"x%5E2-2x%2B1-1-6=0\" or\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2=7\" => \"x-1=sqrt%287%29\", we select the positive root:\r
\n" ); document.write( "\n" ); document.write( "\"x=1%2Bsqrt%287%29\", approximately x=3.65 feet.\r
\n" ); document.write( "\n" ); document.write( "Answer:The length is 3.65 feet and the width is 3.65-2=1.65 feet.
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