document.write( "Question 439410: The product of three consecutive terms in a geometric sequence is -1000, and their sum is 15. Find the common ratio. \n" ); document.write( "
Algebra.Com's Answer #303669 by robertb(5830)\"\" \"About 
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Let a, ar, and \"ar%5E2\" be the terms in geometric sequence.\r
\n" ); document.write( "\n" ); document.write( "Then from the given, \"a%2Aar%2Aar%5E2+=+a%5E3r%5E3+=+%28ar%29%5E3+=+-1000\", or ar = -10, after taking cube roots.
\n" ); document.write( "==> a = -10/r.
\n" ); document.write( "Also, \"a+%2B+ar+%2B+ar%5E2+=+15\"<==> \"a%281%2Br%2Br%5E2%29+=+15\"
\n" ); document.write( "<==> \"%28-10%2Fr%29%281%2Br%2Br%5E2%29+=+15\"
\n" ); document.write( "<==> \"0+=+r%5E2+%2B+5r+%2B+2\", after cross-multiplying and simplifying.
\n" ); document.write( "<==> (2r+1)(r+1) = 0
\n" ); document.write( "==> r = -1/2 or -2
\n" ); document.write( "==> a = 20 or 5, respectively.
\n" ); document.write( "Hence the sequences are {20, -10, 5} and { 5, -10, 20}. (The two sequences are DIFFERENT because they have different first terms and common ratios.)
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