document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45694>Question 45694</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perimeter of a rectangle. The perimeter of a rectangular backyard is 6x + 6 yards. If the width is x yards, find a binomial that represents the length. please show all work and solution. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30363 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30363\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2[length + width] [Formula for a perimeter]<BR>\n" );
document.write( "(6x+6)=2[(length) + (x)] [Plug-in the given values]<BR>\n" );
document.write( "6x+6=2(length) + 2x [Distribute the 2]<BR>\n" );
document.write( "(6x+6) - 2x = 2(length) +2x-2x [Solve for length]<BR>\n" );
document.write( "6x+6-2x=2(length)<BR>\n" );
document.write( "4x+6=2(length)<BR>\n" );
document.write( "(4x+6)/2=2(length)/2<BR>\n" );
document.write( "(4x+6)/2=length<BR>\n" );
document.write( "2(2x+3)/2 = length [Factor and cancel out]<BR>\n" );
document.write( "2x+3=length [Final answer]<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check the answer by plugging (length = 2x+3) back into the original formula.<BR>\n" );
document.write( "P=2[length + width] [Returning to the formula for a perimeter]<BR>\n" );
document.write( "P = 2[(x) + (2x+3)]<BR>\n" );
document.write( "P = 2x+4x + 6<BR>\n" );
document.write( "P = 6x+6 [Checks out] </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );