document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=439370>Question 439370</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the slope of the curve f(x) = (4x - 3)(2x^3 +1) at x = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303617 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Find the slope of the curve f(x) = (4x - 3)(2x^3 +1) at x = 1<BR>\n" );
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document.write( "You will have to apply calculus.<BR>\n" );
document.write( "f(x) = (4x - 3)(2x^3 +1)<BR>\n" );
document.write( "expand with FOIL:<BR>\n" );
document.write( "f(x) = 12x^4 - 6x^3 + 4x - 3<BR>\n" );
document.write( "f'(x) = 48x^3 - 18x^2 + 4<BR>\n" );
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document.write( "now, substitute x=1:<BR>\n" );
document.write( "f'(1) = 48(1)^3 - 18(1)^2 + 4<BR>\n" );
document.write( "f'(1) = 48 - 18 + 4<BR>\n" );
document.write( "f'(1) = 34<BR>\n" );
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document.write( "Slope would be 34\r<BR>\n" );
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