document.write( "Question 439348: Find all values of θ in the interval 0 ≤ θ < 360° that satisfy the equation 2 sin^2 θ + sin θ = 1\r
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document.write( "Kamla \n" );
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Algebra.Com's Answer #303610 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find all values of θ in the interval 0 ≤ θ < 360° that satisfy the equation 2 sin^2 θ + sin θ = 1 \n" ); document.write( "---- \n" ); document.write( "sin^2 + sin -1 = 0 \n" ); document.write( "--- \n" ); document.write( "Use the Quadratic Formula: \n" ); document.write( "theta = [-1 +- sqrt(1-4*1*-1)]/2 \n" ); document.write( "---- \n" ); document.write( "theta = [-1 +- sqrt(5)]/2 \n" ); document.write( "--- \n" ); document.write( "theta = [-1+sqrt(5)]/2 or theta = [-1-sqrt(5)]/2 \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |