document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45673>Question 45673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor completely 16x^3-2y^3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30360 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factor completely 16x^3-2y^3\r<BR>\n" );
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document.write( "Factor out the common factor of \"2\" to get:\r<BR>\n" );
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document.write( "2(8x^3-y^3)\r<BR>\n" );
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document.write( "The 8x^3 - y^3 can be written as (2x)^3 - y^3<BR>\n" );
document.write( "This is the \"difference of cubes\" form and can be factored as follows:\r<BR>\n" );
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document.write( "(2x-y)((2x)^2-(2x)(y)+(y)^2)\r<BR>\n" );
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document.write( "Final Answer: 2(2x-y)(4x^2-2xy+y^2)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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