document.write( "Question 439296: a pizza parlor runs a special where you can buy a lagre pizza with 1 cheese, 1 vegetable, and 2 meats for $12. you have a choice of 5 cheeses, 10 vegetables, and 6 meats. how many different variations of the pizza special are possible? \n" ); document.write( "

Algebra.Com's Answer #303596 by jorel1380(3719) $\"\"$ $\"About$

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You're combining the 6 meats 2 at a time, or 6C2=6x5x4!/2x4!=15. So 5 cheese choices, 10 veggie choices, and 15 meat choices is:
\n" ); document.write( "5x10x15=750 different possible combinations! \n" ); document.write( "

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