document.write( "Question 439276: the perimeter of a rectangle is 204 inches. The length exceeds the width by 30 inches. What is the length and width? \n" ); document.write( "
Algebra.Com's Answer #303593 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "204=2(W+30)+2W \n" ); document.write( "\"=4W+60 \n" ); document.write( "144=4W \n" ); document.write( "36=W \n" ); document.write( "66=L \n" ); document.write( "the rectangle is 66\" by 36\". \n" ); document.write( " |