document.write( "Question 439096: \"1%2F2%2B%28%282x-1%29%2F3%29%3C=1\"
\n" ); document.write( "please help me sole this inequality in interval notation
\n" ); document.write( "thank you
\n" ); document.write( "note the ( ) are actually absolute value brackets
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Algebra.Com's Answer #303561 by lwsshak3(11628)\"\" \"About 
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1/2+|2x-1/3)|<=1
\n" ); document.write( "1/2+|2x-1|/3<=1 (pull out denominator 3)
\n" ); document.write( "LCD=6
\n" ); document.write( "3+2|2x-1|<=6
\n" ); document.write( "solve for two possibilities: (2x-1)>=0 or (2x-1)<0
\n" ); document.write( "..
\n" ); document.write( "3+2(2x-1)<=6
\n" ); document.write( "3+4x-2<=6
\n" ); document.write( "4x>=5
\n" ); document.write( "x>=5/4
\n" ); document.write( "..
\n" ); document.write( "3+2(-2x+1)<=6
\n" ); document.write( "3-4x+2<=6
\n" ); document.write( "-4x>=1 (divide by (-4) and reverse inequality sign
\n" ); document.write( "x<=-1/4
\n" ); document.write( "..\r
\n" ); document.write( "\n" ); document.write( "Solution:
\n" ); document.write( "(-infinity,-1/4] U [5/4,infinity)
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