document.write( "Question 439096:
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document.write( "please help me sole this inequality in interval notation
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document.write( "thank you
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document.write( "note the ( ) are actually absolute value brackets \n" );
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Algebra.Com's Answer #303561 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 1/2+|2x-1/3)|<=1 \n" ); document.write( "1/2+|2x-1|/3<=1 (pull out denominator 3) \n" ); document.write( "LCD=6 \n" ); document.write( "3+2|2x-1|<=6 \n" ); document.write( "solve for two possibilities: (2x-1)>=0 or (2x-1)<0 \n" ); document.write( ".. \n" ); document.write( "3+2(2x-1)<=6 \n" ); document.write( "3+4x-2<=6 \n" ); document.write( "4x>=5 \n" ); document.write( "x>=5/4 \n" ); document.write( ".. \n" ); document.write( "3+2(-2x+1)<=6 \n" ); document.write( "3-4x+2<=6 \n" ); document.write( "-4x>=1 (divide by (-4) and reverse inequality sign \n" ); document.write( "x<=-1/4 \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "Solution: \n" ); document.write( "(-infinity,-1/4] U [5/4,infinity) \n" ); document.write( " |