document.write( "Question 439292: A college crew team can maintain a speed equivalent to 15 km/hr in still water. If it takes the team 50 minutes to row 6 km upstream and back, what is the rate of the current in the river?\r
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document.write( "my teacher gave me the answer 3km/hr but i cant figure out how to set it up. could you also explain as you go through? thank you very much :D \n" );
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Algebra.Com's Answer #303552 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A college crew team can maintain a speed equivalent to 15 km/hr in still water. If it takes the team 50 minutes to row 6 km upstream and back, what is the rate of the current in the river? \n" ); document.write( "----------------- \n" ); document.write( "upstream DATA: \n" ); document.write( "distance = 6 km ; rate = 15-c ; time = d/r = 6/(15-c) hrs. \n" ); document.write( "------------------- \n" ); document.write( "downstream DATA: \n" ); document.write( "distance = 6 km ; rate = 15+c ; time = d/r = 6/(15+c) hrs \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "time + time = (5/6) hr \n" ); document.write( "6/(15-c) + 6/(15+c) = (5/6) hr \n" ); document.write( "----- \n" ); document.write( "6*6(15+c) + 6*6(15-c) = 5*(225-c^2) \n" ); document.write( "1080 = 5(225-c^2) \n" ); document.write( "216 = 225-c^2 \n" ); document.write( "c^2 = 9 \n" ); document.write( "Positive solution: \n" ); document.write( "c = 3 km/hr (speed of the current) \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==============\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "my teacher gave me the answer 3km/hr \n" ); document.write( " |