document.write( "Question 439292: A college crew team can maintain a speed equivalent to 15 km/hr in still water. If it takes the team 50 minutes to row 6 km upstream and back, what is the rate of the current in the river?\r
\n" ); document.write( "\n" ); document.write( "my teacher gave me the answer 3km/hr but i cant figure out how to set it up. could you also explain as you go through? thank you very much :D
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Algebra.Com's Answer #303552 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A college crew team can maintain a speed equivalent to 15 km/hr in still water. If it takes the team 50 minutes to row 6 km upstream and back, what is the rate of the current in the river?
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\n" ); document.write( "upstream DATA:
\n" ); document.write( "distance = 6 km ; rate = 15-c ; time = d/r = 6/(15-c) hrs.
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\n" ); document.write( "downstream DATA:
\n" ); document.write( "distance = 6 km ; rate = 15+c ; time = d/r = 6/(15+c) hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "time + time = (5/6) hr
\n" ); document.write( "6/(15-c) + 6/(15+c) = (5/6) hr
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\n" ); document.write( "6*6(15+c) + 6*6(15-c) = 5*(225-c^2)
\n" ); document.write( "1080 = 5(225-c^2)
\n" ); document.write( "216 = 225-c^2
\n" ); document.write( "c^2 = 9
\n" ); document.write( "Positive solution:
\n" ); document.write( "c = 3 km/hr (speed of the current)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "my teacher gave me the answer 3km/hr
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