document.write( "Question 439180: I have been up for the whole night working on other math h.w. Now im on this one and my brain is completely dead and i can jus not figure it out. I know that to find the perimeter of a square is 4s. Then to find the area is s^4. After that my brains jus goes dead\r
\n" ); document.write( "\n" ); document.write( "The perimeter of square one is 36 cm. greater than the perimeter of square two. The area of squar eone is 243 square cm more than the area of square two. Find the are of the larger square.
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Algebra.Com's Answer #303515 by Gogonati(855)\"\" \"About 
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Let x cm the perimeter of square 2, and x/4 the length of its side.
\n" ); document.write( "Perimeter of square 1 is (x+36) cm and its side (x+36)/4 cm.\r
\n" ); document.write( "\n" ); document.write( "The area of square 2 is:\"%28x%2F4%29%5E2\" and the area of square 1 \"%28%28x%2B36%29%2F4%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Since the areas of these two squares differ with \"243cm%5E2\" we write:\r
\n" ); document.write( "\n" ); document.write( "\"%28%28x%2B36%29%2F4%29%5E2-%28x%2F4%29%5E2=243\", solving the final equation we find x=36 cm.\r
\n" ); document.write( "\n" ); document.write( "The area of a larger square is:\"%28%2836%2B36%29%2F4%29%5E2=324cm%5E2\".
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