document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=439129>Question 439129</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measurement of one of two complementary angles is three greater than twice the measur of the other. Find the measure of each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303505 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The measurement of one of two complementary angles is three greater than twice the measure of the other. Find the measure of each.<BR>\n" );
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document.write( "Let one of the angles be \"x\".<BR>\n" );
document.write( "The other is \"90-x\".<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "90-x = 2x+3<BR>\n" );
document.write( "3x = 87<BR>\n" );
document.write( "x = 29 degrees<BR>\n" );
document.write( "2x+3 = 61 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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