document.write( "Question 45662: Hi again,\r
\n" ); document.write( "\n" ); document.write( "I need some assistance with this mixture problem:\r
\n" ); document.write( "\n" ); document.write( "It takes a pipe 10 minutes less than another one to fill a tank of water. Both pipes together can fill the tank in 12 minutes. How long will it take each one to fill the tank separately?\r
\n" ); document.write( "\n" ); document.write( "I am having trouble on how to start setting the equation up.\r
\n" ); document.write( "\n" ); document.write( "Thanks again,
\n" ); document.write( "Lou
\n" ); document.write( "

Algebra.Com's Answer #30346 by Fermat(136)\"\" \"About 
You can put this solution on YOUR website!
Let the two pipes have fill rates of R1 and R2 m^3/min
\n" ); document.write( "Let the volume of the tank be V m^3
\n" ); document.write( "The time for pipe1 to fill the tank is,
\n" ); document.write( "T1 = V/R1 min
\n" ); document.write( "similiarly,
\n" ); document.write( "T2 = V/R2
\n" ); document.write( "The difference in times is 10 min, so we can write,
\n" ); document.write( "T1 - T2 = 10
\n" ); document.write( "(at the moment it doesn't matter whether you say T1-T2 or T2-T1, since we haven't said which of R1 and R2 is the greater. It will all work out in the end)
\n" ); document.write( "substituting for T1 and T2,
\n" ); document.write( "V/R1 - V/R2 = 10
\n" ); document.write( "V(1/R1 - 1/R2) = 10
\n" ); document.write( "====================
\n" ); document.write( "If pipe1 fills the tank at R1 m^3/min and pipe2 fills the tank at R2 m^3/min, then together they both fill the tank at a rate of (R1+R2) m^3/min.
\n" ); document.write( "T3 = V/(R1+R2)
\n" ); document.write( "12 = V/(R1 + R2)
\n" ); document.write( "================
\n" ); document.write( "You now have two equations in R1 and R2 from which you can solve for R1 and R2 separately, in terms of V.
\n" ); document.write( "You should end up with T1 = 30 mins, T2 = 20 mins.
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