document.write( "Question 45662: Hi again,\r
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document.write( "I need some assistance with this mixture problem:\r
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document.write( "It takes a pipe 10 minutes less than another one to fill a tank of water. Both pipes together can fill the tank in 12 minutes. How long will it take each one to fill the tank separately?\r
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document.write( "I am having trouble on how to start setting the equation up.\r
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document.write( "Thanks again,
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document.write( "Lou \n" );
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Algebra.Com's Answer #30346 by Fermat(136)![]() ![]() You can put this solution on YOUR website! Let the two pipes have fill rates of R1 and R2 m^3/min \n" ); document.write( "Let the volume of the tank be V m^3 \n" ); document.write( "The time for pipe1 to fill the tank is, \n" ); document.write( "T1 = V/R1 min \n" ); document.write( "similiarly, \n" ); document.write( "T2 = V/R2 \n" ); document.write( "The difference in times is 10 min, so we can write, \n" ); document.write( "T1 - T2 = 10 \n" ); document.write( "(at the moment it doesn't matter whether you say T1-T2 or T2-T1, since we haven't said which of R1 and R2 is the greater. It will all work out in the end) \n" ); document.write( "substituting for T1 and T2, \n" ); document.write( "V/R1 - V/R2 = 10 \n" ); document.write( "V(1/R1 - 1/R2) = 10 \n" ); document.write( "==================== \n" ); document.write( "If pipe1 fills the tank at R1 m^3/min and pipe2 fills the tank at R2 m^3/min, then together they both fill the tank at a rate of (R1+R2) m^3/min. \n" ); document.write( "T3 = V/(R1+R2) \n" ); document.write( "12 = V/(R1 + R2) \n" ); document.write( "================ \n" ); document.write( "You now have two equations in R1 and R2 from which you can solve for R1 and R2 separately, in terms of V. \n" ); document.write( "You should end up with T1 = 30 mins, T2 = 20 mins. \n" ); document.write( " |