document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=438983>Question 438983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303455 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303455\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of mg of 45% nickel alloy<BR>\n" );
document.write( "After mixing with 6 mg of pure nickel, total amount of alloy is x + 6<BR>\n" );
document.write( "Therefore the mixture contains this amount of nickel:<BR>\n" );
document.write( "0.45x + 6 = 0.78(x + 6)<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "0.45x + 6 = 0.78x + 4.68<BR>\n" );
document.write( "x = 1.32/0.33 -> x = 4<BR>\n" );
document.write( "Ans: 4 mg<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "(0.45(4) + 6)/(4 + 6) = 7.8/10 = 0.78 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );