document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=438765>Question 438765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It is a variation function problem, I just couldn't find the best topic.\r<BR>\n" );
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document.write( "Here is the problem. I know what the answer is and how to get to the answer I just don't know how I got it. \r<BR>\n" );
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document.write( "From measurements on many rivers, geographers find that the length of a river that drains a particular \"basin\" of land is approximately proportional to the 0.6 power of the area of the basin. The Rio Grande is 3034 kilometers long, and drains a basin of about 500,000 square kilometers.\r<BR>\n" );
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document.write( "To get the particular equation expressing river length in terms of basin area, I know that the equation is going to be y=k*x^0.6 -> 3034=500000^0.6*k which results with y=1.16*x^0.6.<BR>\n" );
document.write( "But why does y have to be 3034? I thought y had to be the dependent variable, and I thought the basin depended on how long the river is, not vice versa. \r<BR>\n" );
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document.write( "Also, if the river in the world is the 6700 kilometer Nile, approximatley what area of land does the Nile drain? (still the same question)<BR>\n" );
document.write( "I think it is a logs question but how would you solve it?\r<BR>\n" );
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document.write( "Thank you!!!!!!! You will be my life-saver ! :D </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303315 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+k%2Ax%5E0.6 ALIGN=MIDDLE  ALT=\"y+=+k%2Ax%5E0.6\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where y = length of river and x = area of the basin.\r<BR>\n" );
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document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3034+=+k%2A500000%5E0.6 ALIGN=MIDDLE  ALT=\"3034+=+k%2A500000%5E0.6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k+=+3034%2F500000%5E0.6+=+1.1551 ALIGN=MIDDLE  ALT=\"k+=+3034%2F500000%5E0.6+=+1.1551\"   DISABLED_style= \"max-width:90%; height:auto;\" >, to 4 decimal places.<BR>\n" );
document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+1.1551x%5E0.6 ALIGN=MIDDLE  ALT=\"y+=+1.1551x%5E0.6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "==> for the Nile River 6700 km long, <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6700+=+1.1551x%5E0.6 ALIGN=MIDDLE  ALT=\"6700+=+1.1551x%5E0.6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E0.6+=+5800.17676 ALIGN=MIDDLE  ALT=\"x%5E0.6+=+5800.17676\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+root%280.6%2C+5800.17676%29+ ALIGN=MIDDLE  ALT=\"x+=+root%280.6%2C+5800.17676%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1,872,414.726 square kilometers of basin is drained. </SPAN>\n" );
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