document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=438602>Question 438602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the ratio of 2 complementary angles is 8:1, what is the degree measure of the samller angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303241 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the ratio of 2 complementary angles is 8:1, what is the degree measure of the samller angle<BR>\n" );
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document.write( "Let one of the ansgles be \"x\"; the other is \"90-x\".<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x/(90-x) = 8/1<BR>\n" );
document.write( "x = 8(90-x)<BR>\n" );
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document.write( "x = 720-8x<BR>\n" );
document.write( "9x = 720<BR>\n" );
document.write( "x = 80 <BR>\n" );
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document.write( "90-x = 10 degrees (smaller angle)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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