document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=438508>Question 438508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A new model computer is advertised as being 6 h faster at a certain processing job than an older model. If 3 of the older models and 2 of the new models work simultaneously, they can finish the job in 1 h. How long would it take one of the new machines to finish the job alone?\r<BR>\n" );
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document.write( "my teacher gave me the answer of 3 hours and i have other problems like this that i could do but for some reason i cant set this one up. thank you :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303216 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303216\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> each machine does some FRACTION of the job based on the individual times<BR>\n" );
document.write( "___ the fractions add to one (the WHOLE job)\r<BR>\n" );
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document.write( "n = time for new machine , n+6 = time for old machine , 1 hr is combined time\r<BR>\n" );
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document.write( "(1/n) + (1/n) + [1/(n+6)] + [1/(n+6)] + [1/(n+6)] = 1\r<BR>\n" );
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document.write( "(2/n) + [3/(n+6)] = 1\r<BR>\n" );
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document.write( "2(n+6) + 3(n) = n(n+6) ___ 2n + 12 + 3n = n^2 + 6n ___ 0 = n^2 + n - 12\r<BR>\n" );
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document.write( "0 = (n+4)(n-3)\r<BR>\n" );
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document.write( "0 = n+4 ___ -4 = n ___ negative value NOT realistic\r<BR>\n" );
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document.write( "0 = n-3 ___ 3 = n </SPAN>\n" );
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