document.write( "Question 438469: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles an hour and train B is traveling at 120 miles an hour. Train A passes a ststion at 5:25 p.m. If train B passes the same station at 5:37 p.m., at what time will train B catch up to train A? \n" ); document.write( "

Algebra.Com's Answer #303212 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Trains A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 100 miles an hour and train B is traveling at 120 miles an hour.
\n" ); document.write( " Train A passes a station at 5:25 p.m.
\n" ); document.write( " If train B passes the same station at 5:37 p.m., at what time will train B catch up to train A?
\n" ); document.write( ":
\n" ); document.write( "From the given information, we know that Train B is 12 min behind A at at 5:25 pm
\n" ); document.write( "therefore Train B is:
\n" ); document.write( " $\"12%2F60\"$ * 120 = 24 miles behind Train A at that time.
\n" ); document.write( ":
\n" ); document.write( "Let t = time required for Train B to catch Train A
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Train B dist = Train A dist + 24 mi
\n" ); document.write( "120t = 100t + 24
\n" ); document.write( "120t - 100t = 24
\n" ); document.write( "20t = 24
\n" ); document.write( "t = $\"24%2F20\"$
\n" ); document.write( "t = 1.2 hrs for B to catch A
\n" ); document.write( ":
\n" ); document.write( "Convert 1.2 hrs to hrs and minutes: 1 + .2(60) = 1 hr 12 min
\n" ); document.write( ":
\n" ); document.write( "Find the time from 5:25 pm:
\n" ); document.write( "5:25 + 1:12 = 6:37 pm, Train B catches Train A \n" ); document.write( "

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