document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45624>Question 45624</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is a question from a pre-test. Is this a trial and error kind of thing?\r<BR>\n" );
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document.write( "Rewrite the middle term as the sum of two terms and then factor completely.\r<BR>\n" );
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document.write( "25x^2+35x+12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30312 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30312\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 25x^2 + 35x + 12<BR>\n" );
document.write( "The factors of the product of the leading coefficient and the constant must sum up to the linear term. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2A25+=+300 ALIGN=MIDDLE  ALT=\"12%2A25+=+300\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "25x^2 + 35x + 12<BR>\n" );
document.write( "25x^2 + 15x + 20x + 12<BR>\n" );
document.write( "(25x^2 + 15x) + (20x + 12)<BR>\n" );
document.write( "5x(5x + 3) + 4(5x + 3)<BR>\n" );
document.write( "(5x + 4)(5x + 3) </SPAN>\n" );
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