document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=438244>Question 438244</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve and check using the substitution method.   x+3y=23 and 3x-2y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303105 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the 1st equation, x = 23 - 3y<BR>\n" );
document.write( "==> 3(23 - 3y) - 2y = 3<BR>\n" );
document.write( "==> 69 - 9y - 2y = 3<BR>\n" );
document.write( "==> 66 = 11y<BR>\n" );
document.write( "==> y = 6<BR>\n" );
document.write( "==> x = 23 - 3*6 = 23 - 18 = 5. </SPAN>\n" );
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