document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=438126>Question 438126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the standard form of the equation of the hyperbola with the given characteristics.<BR>\n" );
document.write( "Vertices (4,-1), (4,3)  Foci: (4,-2) ,(4,4)\r<BR>\n" );
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document.write( "need help solving this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303084 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303084\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The center of the hyperbola is (4, 1).  \r<BR>\n" );
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document.write( "Transverse axis is parallel to the x-axis.\r<BR>\n" );
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document.write( "Here a = 2, and c = (4--2)/2 = 6/2 = 3, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2+=+c%5E2+-+a%5E2+=+9+-+4+=+5 ALIGN=MIDDLE  ALT=\"b%5E2+=+c%5E2+-+a%5E2+=+9+-+4+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "==> The equation is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-4%29%5E2%2F4+-+%28y+-+1%29%5E2%2F5+=+1 ALIGN=MIDDLE  ALT=\"%28x-4%29%5E2%2F4+-+%28y+-+1%29%5E2%2F5+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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