document.write( "Question 438086: For his morning workout a boxer bicycles for 8 miles and then jogs back to camp along the same route. If he bicycles 6 mph faster than he jogs, and the entire workout lasts 2 hours, how fast does he jog? \n" ); document.write( "
Algebra.Com's Answer #303053 by ankor@dixie-net.com(22740)\"\" \"About 
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For his morning workout a boxer bicycles for 8 miles and then jogs back to camp along the same route.
\n" ); document.write( "If he bicycles 6 mph faster than he jogs, and the entire workout lasts 2 hours, how fast does he jog?
\n" ); document.write( ":
\n" ); document.write( "Let x = his jogging speed
\n" ); document.write( "then
\n" ); document.write( "(x+6) = his biking speed
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\n" ); document.write( "Write a time equation Time = dist/speed
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\n" ); document.write( "Jog time + bike time = 2 hrs
\n" ); document.write( "\"8%2Fx\" + \"8%2F%28%28x%2B6%29%29\" = 2
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\n" ); document.write( "multiply by x(x+6), results
\n" ); document.write( "8(x+6) + 8x = 2x(x+6)
\n" ); document.write( "8x + 48 + 8x = 2x^2 + 12x
\n" ); document.write( "16x + 48 = 2x^2 + 12x
\n" ); document.write( ":
\n" ); document.write( "A quadratic equation
\n" ); document.write( "2x^2 + 12x - 16x - 48 = 0
\n" ); document.write( "2x^2 - 4x - 48 = 0
\n" ); document.write( ":
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "x^2 - 2x - 24 = 0
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\n" ); document.write( "Factors to
\n" ); document.write( "(x-6)(x+4) = 0
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\n" ); document.write( "x = 6 mph is the jogging speed
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\n" ); document.write( "Check this by finding the times
\n" ); document.write( "8/6 = 1.33 hrs jogging
\n" ); document.write( "8/12= .67 hrs biking
\n" ); document.write( "----------------------
\n" ); document.write( "total 2 hrs
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