document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=438125>Question 438125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am lost, here is the question... y varies directly as the square of x. If y=162 when r=9, find y when r=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303044 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you mean it varies with r:<BR>\n" );
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document.write( "y = k/r^2<BR>\n" );
document.write( "You can find the constant<BR>\n" );
document.write( "162 = k*(9^2) = k*81<BR>\n" );
document.write( "k = 2<BR>\n" );
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document.write( "at r=3, y = 2*3^2<BR>\n" );
document.write( "y = 18<BR>\n" );
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document.write( "You don't have to find the constant<BR>\n" );
document.write( "at r = 3, y = 162/(9/3)^2 = 162/9 = 18<BR>\n" );
document.write( "r is 1/3, so y is (1/3)^2 of 162<BR>\n" );
document.write( "= 18\r<BR>\n" );
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document.write( " </SPAN>\n" );
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