document.write( "Question 438100: Here is the question from my book.... Brad is performing an experiment in chemistry class at the University of North Carolina. He needs to mix 20 liters of 40% acid solution with a 70% acid solution to get a mixture that is 50% acid. How many liters of the 70% acid solution should he use?\r
\n" ); document.write( "\n" ); document.write( "I think the answer is 15 but when i tried to work it out I got confused. this is what I have so far: 20/15 = 1.333333333, 1.333333333/70= 50, 1.333333333 X 70 = 50, well anyways you see I didn't get to far.
\n" ); document.write( "thank you.
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Algebra.Com's Answer #303035 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
He needs to mix 20 liters of 40% acid solution with a 70% acid solution to get a
\n" ); document.write( " mixture that is 50% acid.
\n" ); document.write( " How many liters of the 70% acid solution should he use?
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\n" ); document.write( "Let x = amt of 70% solution required
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\n" ); document.write( "Write an amt of acid equation in decimal form:
\n" ); document.write( ".40(20) + .70x = .50(x+20)
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\n" ); document.write( "8 + .70x = .50x + 10
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\n" ); document.write( ".70x - .50x = 10 - 8
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\n" ); document.write( ".20x = 2
\n" ); document.write( "x = \"2%2F.2\"
\n" ); document.write( "x = 10 liters of 70% solution
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\n" ); document.write( "Confirm the solution
\n" ); document.write( ".4(20) + .7(10) = .5(10+20)
\n" ); document.write( "8 + 7 = .5(30)
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