document.write( "Question 438062: Pete is planning to take a motorboat ride for 80 miles and then take a rowboat for another 20 miles. He figures his motorboat can travel at a rate that is twice as fast as he can row the rowboat. If he wants to take 3 hours for the trip, how fast will he row the rowboat? \n" ); document.write( "
Algebra.Com's Answer #303026 by ankor@dixie-net.com(22740)\"\" \"About 
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Pete is planning to take a motorboat ride for 80 miles and then take a rowboat for another 20 miles.
\n" ); document.write( " He figures his motorboat can travel at a rate that is twice as fast as he can row the rowboat.
\n" ); document.write( " If he wants to take 3 hours for the trip, how fast will he row the rowboat?
\n" ); document.write( ":
\n" ); document.write( "Let r = speed of the rowboat
\n" ); document.write( "then
\n" ); document.write( "2r = speed of the motorboat
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Rowboat time + motor time = 3 hrs
\n" ); document.write( "\"20%2Fs\" + \"80%2F%282s%29\" = 3
\n" ); document.write( "multiply by 2s
\n" ); document.write( "2s*\"20%2Fs\" + 2s*\"80%2F%282s%29\" = 2s(3)
\n" ); document.write( "Cancel the denominators, results
\n" ); document.write( "2(20) + 80 = 6s
\n" ); document.write( "40 + 80 = 6s
\n" ); document.write( "120 = 6s
\n" ); document.write( "s = \"120%2F6\"
\n" ); document.write( "s = 20 mph, an incredible speed for a rowboat
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution using the time equation
\n" ); document.write( "\"20%2F20\" + \"80%2F40\" =
\n" ); document.write( "1 + 2 = 3 hrs
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