document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970>Question 970</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A piece of wire 38m long is bent into the shape of a rectangle that is twice as long as it is wide . Find its dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #303 by </B><A HREF=/tutors/aboutme.mpl?userid=veeru><B>veeru(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=veeru><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write down the given information:<BR>\n" );
document.write( "A piece of wire is bent into shape of rectangle. So, length of the wire is same as the perimeter of rectangle. <BR>\n" );
document.write( "Recall that the perimeter of a figure is the sum of the measures of its sides.<BR>\n" );
document.write( "Let the length of the rectangle be L and the width be W.<BR>\n" );
document.write( "The sum of the measures of the sides of rectangle is: L + W + L + W<BR>\n" );
document.write( "= 2L + 2W <BR>\n" );
document.write( "= 2(L + W)<BR>\n" );
document.write( "But the perimeter of the rectangle is 38m.<BR>\n" );
document.write( "So, 2(L + W) = 38.            -------- Equation (1)<BR>\n" );
document.write( "Also given that the length is twice the width.<BR>\n" );
document.write( "So, L = 2W.                   -------- Equation (2)\r<BR>\n" );
document.write( "\n" );
document.write( "Substitute the equation 2 in equation 1:<BR>\n" );
document.write( "2(2W + W) = 38<BR>\n" );
document.write( "2(3W) = 38<BR>\n" );
document.write( "6W = 38<BR>\n" );
document.write( "Divide by 6 on both sides:<BR>\n" );
document.write( "W is approximately equal to 6.33.\r<BR>\n" );
document.write( "\n" );
document.write( "Substitute 6.33 for W in the equation 2:<BR>\n" );
document.write( "L = 2(6.33) <BR>\n" );
document.write( "=12.66<BR>\n" );
document.write( "L is approximately equal to 12.66.\r<BR>\n" );
document.write( "\n" );
document.write( "So, the approximate dimensions of the rectangle are 6.33m and 12.66m.<BR>\n" );
document.write( "The final answer can also be expressed as fractions: 17/3 and 38/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );