document.write( "Question 45554: Find a polynomial of lowest degree with only real coefficients and having the given zeros.\r
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document.write( "1+ square root of 3,1- square root of 3, and 7 \n" );
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Algebra.Com's Answer #30291 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! (x - (1 + sqrt(3))(x - (1 - sqrt(3))(x - 7) \n" ); document.write( "(x - 1 - sqrt(3)(x - 1 + sqrt(3))(x - 7) \n" ); document.write( "(x^2 - x - sqrt(3)x - x + 1 + sqrt(3) + sqrt(3)x - sqrt(3) - 3)(x - 7) \n" ); document.write( "(x^2 - 2x - 2)(x - 7) \n" ); document.write( "x^3 - 2x^2 - 2x - 7x^2 + 14x + 14 \n" ); document.write( "x^3 - 9x^2 + 12x + 14 = f(x) \n" ); document.write( " |