document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=437722>Question 437722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Towns A and B are 220 km apart. A bus leaves Town A at 08 30 for Town B at a speed of 30 km/h. It arrives at Town B after stopping for 40 minutes at Town C which is 120 km from Town A. A motorist starts from Town B at 09 00 and travels towards Town A at a speed of 40 km/h. Find graphically when and at what distance from Town A they will meet.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #302909 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=302909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Towns A and B are 220 km apart. A bus leaves Town A at 08 30 for Town B at a speed of 30 km/h.<BR>\n" );
document.write( " It arrives at Town B after stopping for 40 minutes at Town C which is 120 km from Town A.<BR>\n" );
document.write( " A motorist starts from Town B at 09 00 and travels towards Town A at a speed of 40 km/h.<BR>\n" );
document.write( " Find graphically when and at what distance from Town A they will meet.<BR>\n" );
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document.write( "The 40 min layover at C kind of screws things up but if B motorist arrives at C before A motorist, we can ignore it. See if that is true.<BR>\n" );
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document.write( "Town B is 100 km from C<BR>\n" );
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document.write( "Motorist A's time to C: 120/30 = 4 hrs, 8:30 + 4 = 12:30 PM arrival<BR>\n" );
document.write( "Motorist B's time to C: 100/40 = 2.5 hrs, 9:00 + 2:30 = 11:30 AM arrival<BR>\n" );
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document.write( "Motorist B departs C at 11:30<BR>\n" );
document.write( "Motorist A departs A at  8:30<BR>\n" );
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document.write( "Let t = A's travel time till they meet<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(t-3) = B's' travel time, ///I corrected a mistake here<BR>\n" );
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document.write( "A distance expression for each motorist, referenced to City A<BR>\n" );
document.write( "A's dist = 30t; (red line)<BR>\n" );
document.write( "B'a dist = 120 - 40(t-3); green line<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+10%2C+-20%2C+150%2C+30x%2C+120-%2840%28x-3%29%29%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+10%2C+-20%2C+150%2C+30x%2C+120-%2840%28x-3%29%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "Intersect: t = 3.43 hrs, dist ~ 103 mi from A<BR>\n" );
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document.write( "3.43 hrs = 3 hrs 26 min: 8:30 + 3:26 = 11:56 AM they meet 103 mi from A<BR>\n" );
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