document.write( "Question 437868: Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the voltage of the second and 1/3 the voltage of the third battery. Find the actual voltage of each battery.\r
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Algebra.Com's Answer #302898 by Gogonati(855)\"\" \"About 
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Since the batteries are connected in series the total voltage is equal to the sum of voltages connected in series:\r
\n" ); document.write( "\n" ); document.write( "\"U=U%5B1%5D%2BU%5B2%5D%2BU%5B3%5D\"\r
\n" ); document.write( "\n" ); document.write( "Let \"U%5B3%5D=x\" volt the voltage of third battery then the voltage of the first \r
\n" ); document.write( "\n" ); document.write( "is \"U%5B1%5D=%282%2F3%29%2Ax\" and the voltage of the second is \"U%5B2%5D=%281%2F3%29%2Ax\" \r
\n" ); document.write( "\n" ); document.write( "Substitute and have:\"54=%282%2F3%29x%2B%281%2F3%29x%2Bx\", solve this equation:\r
\n" ); document.write( "\n" ); document.write( "\"54=2x\" => \"x=27\"\r
\n" ); document.write( "\n" ); document.write( "Answer: The third battery is 27 v, the second is \"%281%2F3%29%2A27=9v\" and\r
\n" ); document.write( "\n" ); document.write( "the first is \"%282%2F3%29%2A27=18v\"
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