document.write( "Question 437868: Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the voltage of the second and 1/3 the voltage of the third battery. Find the actual voltage of each battery.\r
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Algebra.Com's Answer #302897 by josmiceli(19441)\"\" \"About 
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Let \"b\" = voltage of 2nd battery
\n" ); document.write( "\"2b\" = voltage the 1st battery
\n" ); document.write( "\"+3%2A%282b%29+=+6b+\" = voltage of 3rd battery
\n" ); document.write( "\"+b+%2B+2b+%2B+6b+=+54+\"
\n" ); document.write( "\"+9b+=+54+\"
\n" ); document.write( "\"+b+=+6+\"
\n" ); document.write( "\"+2b+=+12+\"
\n" ); document.write( "\"+6b+=+36+\"
\n" ); document.write( "The batteries are
\n" ); document.write( "6v, 12v, and 36v
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