document.write( "Question 437728: Solve for x.\r
\n" ); document.write( "\n" ); document.write( "log2 (7+2x) + log2 (4x-1) = 3\r
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Algebra.Com's Answer #302849 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi
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document.write( "  2^3 = (2x+7)(4x-1)
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document.write( "    8x^2 +26x -15 = 0
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document.write( "factoring
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document.write( " (4x +15)(2x -1) = 0
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document.write( " (4x +15)= 0
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document.write( "     x = -15/4 Extraneous solution: (7+2x) and (4x-1) are < 0 
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document.write( "  (2x -1) = 0
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document.write( "    x = 1/2 \n" );
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