document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=437759>Question 437759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> last one.... if there are 5 different stat books, 3 dif prob books and 3 dif exam prep books, how many ways can they be arranged if all the books 0f the same type remain next to each other??? Once again...I know it is a permutation but how can I show how to solve the problem rather than plugging the 3's into my calculator?<BR>\n" );
document.write( "Thanks Much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #302816 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=302816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  if there are 5 different stat books, 3 dif prob books and 3 dif exam prep books, how many ways can they be arranged if all the books 0f the same type remain next to each other??? <BR>\n" );
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document.write( "Arrange the 3 types of book: 3! = 6 ways<BR>\n" );
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document.write( "Arrange the books in each of the 3 types: 3!*3!*3! = 6^3 = <BR>\n" );
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document.write( "Ans: 6^4 = 1296<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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