document.write( "Question 437713: when my father was 35 i was 6.now he is twice as old as i am.how old am i?? \n" ); document.write( "

Algebra.Com's Answer #302791 by sudheerb(5) $\"\"$ $\"About$

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Before 'n' years from present, father age is 35 and son age is 6.
\n" ); document.write( "Present age of father is 35 + n.
\n" ); document.write( "Present age of son is 6 + n.
\n" ); document.write( "Present age of father is twice the present age of son.
\n" ); document.write( " (35 + n) = 2(6 + n)
\n" ); document.write( " 35 + n = 2 x 6 + 2 x n
\n" ); document.write( " 35 + n = 12 + 2n [subtract n from both sides of equation]
\n" ); document.write( "35 + n - n = 12 + 2n - n
\n" ); document.write( " 35 = 12 + n. [subtract 12 from both sides of equation]
\n" ); document.write( " 35 - 12 = 12 + n - 12
\n" ); document.write( " 23 = n
\n" ); document.write( " n = 23.
\n" ); document.write( "Therefore present age of son is 6 + n = 6 + 23 = 29 years.
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