document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45556>Question 45556</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm lost.. Solve the system by graphing :( \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30276 by </B><A HREF=/tutors/aboutme.mpl?userid=prabhjyot><B>prabhjyot(165)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=prabhjyot><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1x-2y = 8<BR>\n" );
document.write( "      3x-2y = 12\r<BR>\n" );
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document.write( "Using Substitution Method.\r<BR>\n" );
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document.write( "Expressing x as a function of y (from the first equation) x = (8 +2y)/1\r<BR>\n" );
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document.write( "Substituting this expression into the second equation:\r<BR>\n" );
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document.write( "	3(8-2y)/1-2y = 12\r<BR>\n" );
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document.write( "Simplifying this expression:\r<BR>\n" );
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document.write( "	4y = -12\r<BR>\n" );
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document.write( "or\r<BR>\n" );
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document.write( "	 y = -3\r<BR>\n" );
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document.write( "	Now, substituting y = -3 back into the x expressed as a function of y:\r<BR>\n" );
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document.write( "	x = (8+2y)/1 = 2\r<BR>\n" );
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