document.write( "Question 437604: The parametric equations for a curve in the x-y plane are x=2+t^2 and y=4-3t. Determine the points where the curve intersects the x-axis. \r
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #302727 by stanbon(75887) ![]() You can put this solution on YOUR website! The parametric equations for a curve in the x-y plane are x=2+t^2 and y=4-3t. Determine the points where the curve intersects the x-axis. \n" ); document.write( "----- \n" ); document.write( "When the curve hits the x-axis y = 0. \n" ); document.write( "--- \n" ); document.write( "Solve: 4-3t = 0 \n" ); document.write( "t = (4/3) \n" ); document.write( "---- \n" ); document.write( "Then x = 2+t^2 \n" ); document.write( "x = 2+(4/3)^2 \n" ); document.write( "x = 18/9 + 16/9 \n" ); document.write( "x = 34/9 \n" ); document.write( "------------------------- \n" ); document.write( "The curve intersects at (34/9,0) \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |